Base | Representation |
---|---|
bin | 111000011001011111… |
… | …0011110000001111100 |
3 | 102120121122221222120100 |
4 | 1300302332132001330 |
5 | 3441020231233040 |
6 | 131350020121100 |
7 | 11515216512510 |
oct | 1606276360174 |
9 | 376548858510 |
10 | 121114321020 |
11 | 47400970a90 |
12 | 1b580b36190 |
13 | b562010614 |
14 | 5c0d332140 |
15 | 323cc19b30 |
hex | 1c32f9e07c |
121114321020 has 144 divisors (see below), whose sum is σ = 458032393728. Its totient is φ = 25166609280.
The previous prime is 121114321001. The next prime is 121114321039. The reversal of 121114321020 is 20123411121.
121114321020 is a `hidden beast` number, since 1 + 211 + 1 + 432 + 1 + 0 + 20 = 666.
It is an interprime number because it is at equal distance from previous prime (121114321001) and next prime (121114321039).
It is a super-2 number, since 2×1211143210202 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 121114320984 and 121114321002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4355344 + ... + 4383063.
It is an arithmetic number, because the mean of its divisors is an integer number (3180780512).
Almost surely, 2121114321020 is an apocalyptic number.
121114321020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
121114321020 is an abundant number, since it is smaller than the sum of its proper divisors (336918072708).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121114321020 is a wasteful number, since it uses less digits than its factorization.
121114321020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8738440 (or 8738435 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 121114321020 its reverse (20123411121), we get a palindrome (141237732141).
The spelling of 121114321020 in words is "one hundred twenty-one billion, one hundred fourteen million, three hundred twenty-one thousand, twenty".
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