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121121110221120 = 2632542055941049
BaseRepresentation
bin11011100010100010110100…
…101111111110000101000000
3120212212001202102110010222200
4123202202310233332011000
5111333422013204033440
61105334134143433200
734340466010631652
oct3342426457760500
9525761672403880
10121121110221120
11356581a110a839
12117020ba8b5800
1352778968cb939
1421ca41605c6d2
15e00988576c30
hex6e28b4bfe140

121121110221120 has 84 divisors (see below), whose sum is σ = 416606152041300. Its totient is φ = 32298962724864.

The previous prime is 121121110221073. The next prime is 121121110221131. The reversal of 121121110221120 is 21122011121121.

It is a happy number.

121121110221120 is a `hidden beast` number, since 1 + 211 + 2 + 1 + 110 + 221 + 120 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 34955338588416 + 86165771632704 = 5912304^2 + 9282552^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 121121110221093 and 121121110221102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 21027967645 + ... + 21027973404.

Almost surely, 2121121110221120 is an apocalyptic number.

121121110221120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

121121110221120 is an abundant number, since it is smaller than the sum of its proper divisors (295485041820180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121121110221120 is a wasteful number, since it uses less digits than its factorization.

121121110221120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42055941072 (or 42055941059 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 18.

Adding to 121121110221120 its reverse (21122011121121), we get a palindrome (142243121342241).

Subtracting from 121121110221120 its reverse (21122011121121), we obtain a palindrome (99999099099999).

The spelling of 121121110221120 in words is "one hundred twenty-one trillion, one hundred twenty-one billion, one hundred ten million, two hundred twenty-one thousand, one hundred twenty".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 16 18 20 24 30 32 36 40 45 48 60 64 72 80 90 96 120 144 160 180 192 240 288 320 360 480 576 720 960 1440 2880 42055941049 84111882098 126167823147 168223764196 210279705245 252335646294 336447528392 378503469441 420559410490 504671292588 630839115735 672895056784 757006938882 841118820980 1009342585176 1261678231470 1345790113568 1514013877764 1682237641960 1892517347205 2018685170352 2523356462940 2691580227136 3028027755528 3364475283920 3785034694410 4037370340704 5046712925880 6056055511056 6728950567840 7570069388820 8074740681408 10093425851760 12112111022112 13457901135680 15140138777640 20186851703520 24224222044224 30280277555280 40373703407040 60560555110560 121121110221120