Base | Representation |
---|---|
bin | 1011111100011100101010… |
… | …0110100001100011011100 |
3 | 1201111111212022012111000100 |
4 | 2333013022212201203130 |
5 | 3210133104203323122 |
6 | 43533134102101100 |
7 | 2523556545064116 |
oct | 277071246414334 |
9 | 51444768174010 |
10 | 13133114120412 |
11 | 42037a45a5660 |
12 | 158135141a790 |
13 | 7435a7a90140 |
14 | 335908d223b6 |
15 | 17b950ad2aac |
hex | bf1ca9a18dc |
13133114120412 has 144 divisors (see below), whose sum is σ = 39219256702080. Its totient is φ = 3653075203200.
The previous prime is 13133114120387. The next prime is 13133114120419. The reversal of 13133114120412 is 21402141133131.
13133114120412 is a `hidden beast` number, since 1 + 3 + 13 + 3 + 114 + 120 + 412 = 666.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13133114120419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6204514 + ... + 8047497.
It is an arithmetic number, because the mean of its divisors is an integer number (272355949320).
Almost surely, 213133114120412 is an apocalyptic number.
13133114120412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13133114120412 is an abundant number, since it is smaller than the sum of its proper divisors (26086142581668).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13133114120412 is a wasteful number, since it uses less digits than its factorization.
13133114120412 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14252224 (or 14252219 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 13133114120412 its reverse (21402141133131), we get a palindrome (34535255253543).
It can be divided in two parts, 13133114 and 120412, that added together give a triangular number (13253526 = T5148).
The spelling of 13133114120412 in words is "thirteen trillion, one hundred thirty-three billion, one hundred fourteen million, one hundred twenty thousand, four hundred twelve".
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