Base | Representation |
---|---|
bin | 111110011011001100… |
… | …0011110001111001110 |
3 | 110211000121201020202100 |
4 | 1330312120132033032 |
5 | 4144021412334100 |
6 | 141330141135530 |
7 | 12454020232212 |
oct | 1746630361716 |
9 | 424017636670 |
10 | 134056371150 |
11 | 51942365889 |
12 | 21b9325a5a6 |
13 | c8453a2550 |
14 | 66ba0d4942 |
15 | 3749021400 |
hex | 1f3661e3ce |
134056371150 has 72 divisors (see below), whose sum is σ = 387869784120. Its totient is φ = 32998489920.
The previous prime is 134056371133. The next prime is 134056371151. The reversal of 134056371150 is 51173650431.
134056371150 is a `hidden beast` number, since 1 + 3 + 4 + 0 + 5 + 637 + 1 + 15 + 0 = 666.
It is a super-2 number, since 2×1340563711502 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134056371151) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 11451960 + ... + 11463659.
It is an arithmetic number, because the mean of its divisors is an integer number (5387080335).
Almost surely, 2134056371150 is an apocalyptic number.
134056371150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
134056371150 is an abundant number, since it is smaller than the sum of its proper divisors (253813412970).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134056371150 is a wasteful number, since it uses less digits than its factorization.
134056371150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22915650 (or 22915642 counting only the distinct ones).
The product of its (nonzero) digits is 37800, while the sum is 36.
The spelling of 134056371150 in words is "one hundred thirty-four billion, fifty-six million, three hundred seventy-one thousand, one hundred fifty".
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