Base | Representation |
---|---|
bin | 10011110110011100101… |
… | …000101011101110101000 |
3 | 11211102001202001012210100 |
4 | 103312130220223232220 |
5 | 134322220412342100 |
6 | 2522401314345400 |
7 | 200361322205514 |
oct | 23663450535650 |
9 | 4742052035710 |
10 | 1364132543400 |
11 | 486586292280 |
12 | 1a046528b260 |
13 | 9b838a72383 |
14 | 4a04ac15144 |
15 | 2573e380400 |
hex | 13d9ca2bba8 |
1364132543400 has 144 divisors (see below), whose sum is σ = 4997685663360. Its totient is φ = 330698793600.
The previous prime is 1364132543387. The next prime is 1364132543401. The reversal of 1364132543400 is 43452314631.
1364132543400 is a `hidden beast` number, since 1 + 3 + 6 + 41 + 32 + 543 + 40 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is not an unprimeable number, because it can be changed into a prime (1364132543401) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 34427992 + ... + 34467591.
It is an arithmetic number, because the mean of its divisors is an integer number (34706150440).
Almost surely, 21364132543400 is an apocalyptic number.
1364132543400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1364132543400 is an abundant number, since it is smaller than the sum of its proper divisors (3633553119960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1364132543400 is a wasteful number, since it uses less digits than its factorization.
1364132543400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68895616 (or 68895604 counting only the distinct ones).
The product of its (nonzero) digits is 103680, while the sum is 36.
The spelling of 1364132543400 in words is "one trillion, three hundred sixty-four billion, one hundred thirty-two million, five hundred forty-three thousand, four hundred".
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