Base | Representation |
---|---|
bin | 11100001110100010… |
… | …11111101001100010 |
3 | 1110010010200220022100 |
4 | 32013101133221202 |
5 | 222014012142010 |
6 | 10543431351230 |
7 | 1044353243364 |
oct | 160721375142 |
9 | 43103626270 |
10 | 15154412130 |
11 | 64772a8150 |
12 | 2b2b222516 |
13 | 1576831290 |
14 | a3a93ad34 |
15 | 5da6662c0 |
hex | 38745fa62 |
15154412130 has 96 divisors (see below), whose sum is σ = 46289880000. Its totient is φ = 3391194240.
The previous prime is 15154412101. The next prime is 15154412149. The reversal of 15154412130 is 3121445151.
15154412130 is a `hidden beast` number, since 1 + 5 + 1 + 5 + 441 + 213 + 0 = 666.
It is a super-2 number, since 2×151544121302 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 15154412094 and 15154412103.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 575880 + ... + 601619.
It is an arithmetic number, because the mean of its divisors is an integer number (482186250).
Almost surely, 215154412130 is an apocalyptic number.
15154412130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
15154412130 is an abundant number, since it is smaller than the sum of its proper divisors (31135467870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
15154412130 is a wasteful number, since it uses less digits than its factorization.
15154412130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1177536 (or 1177533 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 15154412130 its reverse (3121445151), we get a palindrome (18275857281).
The spelling of 15154412130 in words is "fifteen billion, one hundred fifty-four million, four hundred twelve thousand, one hundred thirty".
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