| Base | Representation |
|---|---|
| bin | 11101010010000001101… |
| … | …110010101101111111100 |
| 3 | 21010100220011000012202020 |
| 4 | 131102001232111233330 |
| 5 | 230432012100244400 |
| 6 | 4140222425400140 |
| 7 | 265243500111165 |
| oct | 35220156255774 |
| 9 | 7110804005666 |
| 10 | 2012221103100 |
| 11 | 70641839949a |
| 12 | 285b94939050 |
| 13 | 1179a0461720 |
| 14 | 6d56b9c476c |
| 15 | 37520d752a0 |
| hex | 1d481b95bfc |
2012221103100 has 144 divisors (see below), whose sum is σ = 6275441783520. Its totient is φ = 494876160000.
The previous prime is 2012221103099. The next prime is 2012221103117. The reversal of 2012221103100 is 13011222102.
It is a super-2 number, since 2×20122211031002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 2012221103100.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4174600 + ... + 4631600.
It is an arithmetic number, because the mean of its divisors is an integer number (43579456830).
Almost surely, 22012221103100 is an apocalyptic number.
2012221103100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2012221103100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3137720891760).
2012221103100 is an abundant number, since it is smaller than the sum of its proper divisors (4263220680420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2012221103100 is a wasteful number, since it uses less digits than its factorization.
2012221103100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 458160 (or 458153 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 2012221103100 its reverse (13011222102), we get a palindrome (2025232325202).
The spelling of 2012221103100 in words is "two trillion, twelve billion, two hundred twenty-one million, one hundred three thousand, one hundred".
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