Base | Representation |
---|---|
bin | 10111011100100111001101… |
… | …101101010111011010000100 |
3 | 111112010022011011111202111110 |
4 | 113130213031231113122010 |
5 | 102004014431141000200 |
6 | 1003153140401005020 |
7 | 30502161316145055 |
oct | 2734471555273204 |
9 | 445108134452443 |
10 | 103121321031300 |
11 | 2a94856339a380 |
12 | b695729923770 |
13 | 45703b674cb20 |
14 | 1b6715468872c |
15 | bdc64ee60b50 |
hex | 5dc9cdb57684 |
103121321031300 has 144 divisors (see below), whose sum is σ = 350525956277952. Its totient is φ = 23076099801600.
The previous prime is 103121321031259. The next prime is 103121321031353. The reversal of 103121321031300 is 3130123121301.
It is a happy number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1201837299 + ... + 1201923098.
It is an arithmetic number, because the mean of its divisors is an integer number (2434208029708).
Almost surely, 2103121321031300 is an apocalyptic number.
103121321031300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
103121321031300 is an abundant number, since it is smaller than the sum of its proper divisors (247404635246652).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103121321031300 is a wasteful number, since it uses less digits than its factorization.
103121321031300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2403760438 (or 2403760431 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 103121321031300 its reverse (3130123121301), we get a palindrome (106251444152601).
The spelling of 103121321031300 in words is "one hundred three trillion, one hundred twenty-one billion, three hundred twenty-one million, thirty-one thousand, three hundred".
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