Base | Representation |
---|---|
bin | 100010010101100… |
… | …1000001101000000 |
3 | 2222021222121120020 |
4 | 1010223020031000 |
5 | 4324423001410 |
6 | 310154413440 |
7 | 40360111536 |
oct | 10453101500 |
9 | 2867877506 |
10 | 1152156480 |
11 | 5413a9242 |
12 | 281a31280 |
13 | 1549127c7 |
14 | ad038156 |
15 | 6b239a70 |
hex | 44ac8340 |
1152156480 has 112 divisors (see below), whose sum is σ = 3817217664. Its totient is φ = 293877760.
The previous prime is 1152156463. The next prime is 1152156529. The reversal of 1152156480 is 846512511.
It is a super-3 number, since 3×11521564803 (a number of 28 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4011 + ... + 48170.
Almost surely, 21152156480 is an apocalyptic number.
1152156480 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1152156480, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1908608832).
1152156480 is an abundant number, since it is smaller than the sum of its proper divisors (2665061184).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1152156480 is a wasteful number, since it uses less digits than its factorization.
1152156480 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52224 (or 52214 counting only the distinct ones).
The product of its (nonzero) digits is 9600, while the sum is 33.
The square root of 1152156480 is about 33943.4305867866. The cubic root of 1152156480 is about 1048.3440200732.
Adding to 1152156480 its reverse (846512511), we get a palindrome (1998668991).
The spelling of 1152156480 in words is "one billion, one hundred fifty-two million, one hundred fifty-six thousand, four hundred eighty".
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