Base | Representation |
---|---|
bin | 111100110010001000… |
… | …1110100100110000000 |
3 | 110110220221212210022210 |
4 | 1321210101310212000 |
5 | 4114312020143402 |
6 | 135544301102120 |
7 | 12300455461335 |
oct | 1714421644600 |
9 | 413827783283 |
10 | 130531412352 |
11 | 503a36410a0 |
12 | 2136a857940 |
13 | c403007703 |
14 | 6463cba98c |
15 | 35de83406c |
hex | 1e64474980 |
130531412352 has 128 divisors (see below), whose sum is σ = 378605721600. Its totient is φ = 39517194240.
The previous prime is 130531412317. The next prime is 130531412353. The reversal of 130531412352 is 253214135031.
It is a tau number, because it is divible by the number of its divisors (128).
It is a super-2 number, since 2×1305314123522 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130531412353) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4577274 + ... + 4605702.
It is an arithmetic number, because the mean of its divisors is an integer number (2957857200).
Almost surely, 2130531412352 is an apocalyptic number.
130531412352 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130531412352, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (189302860800).
130531412352 is an abundant number, since it is smaller than the sum of its proper divisors (248074309248).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130531412352 is a wasteful number, since it uses less digits than its factorization.
130531412352 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29544 (or 29532 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 130531412352 its reverse (253214135031), we get a palindrome (383745547383).
The spelling of 130531412352 in words is "one hundred thirty billion, five hundred thirty-one million, four hundred twelve thousand, three hundred fifty-two".
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