13121113231200 has 144 divisors (see below), whose sum is σ = 45994548566736. Its totient is φ = 3229812480000.

The previous prime is 13121113231199. The next prime is 13121113231211. The reversal of 13121113231200 is 213231112131.

It is a super-3 number, since 3×13121113231200³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 210243051 + ... + 210305450.

It is an arithmetic number, because the mean of its divisors is an integer number (319406587269).

Almost surely, 2^{13121113231200} is an apocalyptic number.

13121113231200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13121113231200 is an abundant number, since it is smaller than the sum of its proper divisors (32873435335536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121113231200 is a wasteful number, since it uses less digits than its factorization.

13121113231200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 420548537 (or 420548524 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 13121113231200 its reverse (213231112131), we get a palindrome (13334344343331).

The spelling of 13121113231200 in words is "thirteen trillion, one hundred twenty-one billion, one hundred thirteen million, two hundred thirty-one thousand, two hundred".