Base | Representation |
---|---|
bin | 11000100110111010… |
… | …01000000001000000 |
3 | 1021002201101210001120 |
4 | 30103131020001000 |
5 | 204024043212000 |
6 | 10022540032240 |
7 | 645250142166 |
oct | 142335100100 |
9 | 37081353046 |
10 | 13211304000 |
11 | 566a489264 |
12 | 2688532680 |
13 | 13270b625b |
14 | 8d4851236 |
15 | 524c906a0 |
hex | 313748040 |
13211304000 has 112 divisors (see below), whose sum is σ = 43623805056. Its totient is φ = 3523008000.
The previous prime is 13211303951. The next prime is 13211304023. The reversal of 13211304000 is 40311231.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 251236 + ... + 299235.
Almost surely, 213211304000 is an apocalyptic number.
13211304000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13211304000 is an abundant number, since it is smaller than the sum of its proper divisors (30412501056).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13211304000 is an equidigital number, since it uses as much as digits as its factorization.
13211304000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 550501 (or 550481 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 13211304000 its reverse (40311231), we get a palindrome (13251615231).
The spelling of 13211304000 in words is "thirteen billion, two hundred eleven million, three hundred four thousand".
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