Search a number
-
+
13300011363540 = 223511171185384257
BaseRepresentation
bin1100000110001010011001…
…1100111110110011010100
31202002110122122210212212110
43001202212130332303110
53220401410402113130
644141535121151020
72541615452202636
oct301424634766324
952073578725773
1013300011363540
114268559758650
1215a976aa8b470
13756254c653c5
1433da1c884a56
15180e6cd3cab0
hexc18a673ecd4

13300011363540 has 96 divisors (see below), whose sum is σ = 43015223954304. Its totient is φ = 3034583695360.

The previous prime is 13300011363517. The next prime is 13300011363547. The reversal of 13300011363540 is 4536311000331.

13300011363540 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 13300011363498 and 13300011363507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300011363547) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 592680909 + ... + 592703348.

It is an arithmetic number, because the mean of its divisors is an integer number (448075249524).

Almost surely, 213300011363540 is an apocalyptic number.

13300011363540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13300011363540 is an abundant number, since it is smaller than the sum of its proper divisors (29715212590764).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13300011363540 is a wasteful number, since it uses less digits than its factorization.

13300011363540 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1185384297 (or 1185384295 counting only the distinct ones).

The product of its (nonzero) digits is 9720, while the sum is 30.

Adding to 13300011363540 its reverse (4536311000331), we get a palindrome (17836322363871).

The spelling of 13300011363540 in words is "thirteen trillion, three hundred billion, eleven million, three hundred sixty-three thousand, five hundred forty".

Divisors: 1 2 3 4 5 6 10 11 12 15 17 20 22 30 33 34 44 51 55 60 66 68 85 102 110 132 165 170 187 204 220 255 330 340 374 510 561 660 748 935 1020 1122 1870 2244 2805 3740 5610 11220 1185384257 2370768514 3556152771 4741537028 5926921285 7112305542 11853842570 13039226827 14224611084 17780763855 20151532369 23707685140 26078453654 35561527710 39117680481 40303064738 52156907308 60454597107 65196134135 71123055420 78235360962 80606129476 100757661845 120909194214 130392268270 156470721924 195588402405 201515323690 221666856059 241818388428 260784536540 302272985535 391176804810 403030647380 443333712118 604545971070 665000568177 782353609620 886667424236 1108334280295 1209091942140 1330001136354 2216668560590 2660002272708 3325002840885 4433337121180 6650005681770 13300011363540