Base | Representation |
---|---|
bin | 11111000000100011100… |
… | …001011100111000000000 |
3 | 21112201020001211011002210 |
4 | 133000203201130320000 |
5 | 234403040314003100 |
6 | 4310531040542120 |
7 | 306644453011311 |
oct | 37004341347000 |
9 | 7481201734083 |
10 | 2130899750400 |
11 | 7517893a1793 |
12 | 2a4b96021940 |
13 | 125c34975a95 |
14 | 751c964c608 |
15 | 3a669d1dc50 |
hex | 1f02385ce00 |
2130899750400 has 120 divisors (see below), whose sum is σ = 7039294271064. Its totient is φ = 568239923200.
The previous prime is 2130899750387. The next prime is 2130899750401. The reversal of 2130899750400 is 40579980312.
It is a tau number, because it is divible by the number of its divisors (120).
It is a Harshad number since it is a multiple of its sum of digits (48).
It is a self number, because there is not a number n which added to its sum of digits gives 2130899750400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2130899750401) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27707691 + ... + 27784490.
Almost surely, 22130899750400 is an apocalyptic number.
2130899750400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2130899750400 is an abundant number, since it is smaller than the sum of its proper divisors (4908394520664).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2130899750400 is an equidigital number, since it uses as much as digits as its factorization.
2130899750400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55492212 (or 55492191 counting only the distinct ones).
The product of its (nonzero) digits is 544320, while the sum is 48.
The spelling of 2130899750400 in words is "two trillion, one hundred thirty billion, eight hundred ninety-nine million, seven hundred fifty thousand, four hundred".
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