Base | Representation |
---|---|
bin | 110000101010010001100110… |
… | …101000001100111110000000 |
3 | 1001001202021201002210120000021 |
4 | 300222101212220030332000 |
5 | 211022330222133140000 |
6 | 2035055242530303224 |
7 | 63035544546304660 |
oct | 6052214650147600 |
9 | 1031667632716007 |
10 | 214011352240000 |
11 | 62210783090967 |
12 | 20004a00a27b14 |
13 | 92552510c90b3 |
14 | 3abc2c1a541a0 |
15 | 19b1dd690911a |
hex | c2a466a0cf80 |
214011352240000 has 160 divisors (see below), whose sum is σ = 608877585241200. Its totient is φ = 73375320576000.
The previous prime is 214011352239967. The next prime is 214011352240067. The reversal of 214011352240000 is 42253110412.
It is a tau number, because it is divible by the number of its divisors (160).
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 190521565 + ... + 191641564.
Almost surely, 2214011352240000 is an apocalyptic number.
214011352240000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
214011352240000 is an abundant number, since it is smaller than the sum of its proper divisors (394866233001200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
214011352240000 is an frugal number, since it uses more digits than its factorization.
214011352240000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 382163170 (or 382163143 counting only the distinct ones).
The product of its (nonzero) digits is 1920, while the sum is 25.
The spelling of 214011352240000 in words is "two hundred fourteen trillion, eleven billion, three hundred fifty-two million, two hundred forty thousand".
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