Base | Representation |
---|---|
bin | 11001101110010001011101… |
… | …101110011100100011010100 |
3 | 112211120012220200012010010210 |
4 | 121232101131232130203110 |
5 | 104312014302311031200 |
6 | 1040335400300245420 |
7 | 32554305626264151 |
oct | 3156213556344324 |
9 | 484505820163123 |
10 | 113131011033300 |
11 | 33057657455307 |
12 | 1083166a840870 |
13 | 4b182932a7030 |
14 | 1dd17da6c3228 |
15 | d12be592a650 |
hex | 66e45db9c8d4 |
113131011033300 has 144 divisors (see below), whose sum is σ = 373240193723712. Its totient is φ = 26209537382400.
The previous prime is 113131011033251. The next prime is 113131011033367. The reversal of 113131011033300 is 3330110131311.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 853108746 + ... + 853241345.
It is an arithmetic number, because the mean of its divisors is an integer number (2591945789748).
Almost surely, 2113131011033300 is an apocalyptic number.
113131011033300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113131011033300 is an abundant number, since it is smaller than the sum of its proper divisors (260109182690412).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113131011033300 is a wasteful number, since it uses less digits than its factorization.
113131011033300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1706350138 (or 1706350131 counting only the distinct ones).
The product of its (nonzero) digits is 243, while the sum is 21.
Adding to 113131011033300 its reverse (3330110131311), we get a palindrome (116461121164611).
The spelling of 113131011033300 in words is "one hundred thirteen trillion, one hundred thirty-one billion, eleven million, thirty-three thousand, three hundred".
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