Base | Representation |
---|---|
bin | 1011110110100000101011… |
… | …0000010001010101001000 |
3 | 1201010202120112201100101200 |
4 | 2331220022300101111020 |
5 | 3202000203431431440 |
6 | 43414224305344200 |
7 | 2513316040430514 |
oct | 275501260212510 |
9 | 51122515640350 |
10 | 13031111202120 |
11 | 417451060a390 |
12 | 1565624938060 |
13 | 736aa0323c5b |
14 | 3309cdc87144 |
15 | 178e80b0ac30 |
hex | bda0ac11548 |
13031111202120 has 96 divisors (see below), whose sum is σ = 46201212457920. Its totient is φ = 3159057260160.
The previous prime is 13031111202119. The next prime is 13031111202127. The reversal of 13031111202120 is 2120211113031.
13031111202120 is a `hidden beast` number, since 1 + 30 + 311 + 1 + 1 + 202 + 120 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 13031111202093 and 13031111202102.
It is not an unprimeable number, because it can be changed into a prime (13031111202127) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1645338364 + ... + 1645346283.
It is an arithmetic number, because the mean of its divisors is an integer number (481262629770).
Almost surely, 213031111202120 is an apocalyptic number.
13031111202120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13031111202120 is an abundant number, since it is smaller than the sum of its proper divisors (33170101255800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13031111202120 is a wasteful number, since it uses less digits than its factorization.
13031111202120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3290684675 (or 3290684668 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 13031111202120 its reverse (2120211113031), we get a palindrome (15151322315151).
It can be divided in two parts, 13031111 and 202120, that added together give a palindrome (13233231).
The spelling of 13031111202120 in words is "thirteen trillion, thirty-one billion, one hundred eleven million, two hundred two thousand, one hundred twenty".
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