131403310413440 has 128 divisors (see below), whose sum is σ = 353009061014400. Its totient is φ = 46408660733952.

The previous prime is 131403310413439. The next prime is 131403310413451. The reversal of 131403310413440 is 44314013304131.

It is a tau number, because it is divible by the number of its divisors (128).

It is a super-2 number, since 2×131403310413440² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (32).

It is a junction number, because it is equal to n+sod(n) for n = 131403310413397 and 131403310413406.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 343149230 + ... + 343531949.

It is an arithmetic number, because the mean of its divisors is an integer number (2757883289175).

Almost surely, 2^{131403310413440} is an apocalyptic number.

131403310413440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131403310413440 is an abundant number, since it is smaller than the sum of its proper divisors (221605750600960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131403310413440 is a wasteful number, since it uses less digits than its factorization.

131403310413440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 686681234 (or 686681222 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 131403310413440 its reverse (44314013304131), we get a palindrome (175717323717571).

The spelling of 131403310413440 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred ten million, four hundred thirteen thousand, four hundred forty".