Base | Representation |
---|---|
bin | 10110010001110111101… |
… | …000011111100110110100 |
3 | 12102100211002200211010110 |
4 | 112101313220133212310 |
5 | 200041004424230200 |
6 | 3131201102423020 |
7 | 215416663461663 |
oct | 26216750374664 |
9 | 5370732624113 |
10 | 1531015461300 |
11 | 540333350536 |
12 | 208879b91a70 |
13 | b14b2ca0180 |
14 | 5415c8c8dda |
15 | 29c5a20ab50 |
hex | 16477a1f9b4 |
1531015461300 has 72 divisors (see below), whose sum is σ = 4770487162336. Its totient is φ = 376865343360.
The previous prime is 1531015461277. The next prime is 1531015461301. The reversal of 1531015461300 is 31645101351.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1531015461301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 196280134 + ... + 196287933.
Almost surely, 21531015461300 is an apocalyptic number.
1531015461300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1531015461300 is an abundant number, since it is smaller than the sum of its proper divisors (3239471701036).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1531015461300 is a wasteful number, since it uses less digits than its factorization.
1531015461300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 392568097 (or 392568090 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 30.
The spelling of 1531015461300 in words is "one trillion, five hundred thirty-one billion, fifteen million, four hundred sixty-one thousand, three hundred".
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