| Base | Representation |
|---|---|
| bin | 110111111001001101… |
| … | …0010111000001100000 |
| 3 | 102110211011201022221100 |
| 4 | 1233302122113001200 |
| 5 | 3431310431111222 |
| 6 | 131050323154400 |
| 7 | 11446324425525 |
| oct | 1576232270140 |
| 9 | 373734638840 |
| 10 | 120031113312 |
| 11 | 469a5486000 |
| 12 | 1b31a215a00 |
| 13 | b41b78c006 |
| 14 | 5b4952514c |
| 15 | 31c7a9e4ac |
| hex | 1bf2697060 |
120031113312 has 144 divisors (see below), whose sum is σ = 375447880080. Its totient is φ = 36372948480.
The previous prime is 120031113287. The next prime is 120031113313. The reversal of 120031113312 is 213311130021.
120031113312 is a `hidden beast` number, since 1 + 20 + 0 + 311 + 1 + 331 + 2 = 666.
It is a tau number, because it is divible by the number of its divisors (144).
It is a super-3 number, since 3×1200311133123 (a number of 34 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120031113313) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 226764 + ... + 539892.
It is an arithmetic number, because the mean of its divisors is an integer number (2607276945).
Almost surely, 2120031113312 is an apocalyptic number.
120031113312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 120031113312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (187723940040).
120031113312 is an abundant number, since it is smaller than the sum of its proper divisors (255416766768).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120031113312 is a wasteful number, since it uses less digits than its factorization.
120031113312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 313178 (or 313145 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 120031113312 its reverse (213311130021), we get a palindrome (333342243333).
The spelling of 120031113312 in words is "one hundred twenty billion, thirty-one million, one hundred thirteen thousand, three hundred twelve".
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