Base | Representation |
---|---|
bin | 11101100101011000001111… |
… | …101110100100111011000000 |
3 | 122001200120211012122222012110 |
4 | 131211120033232210323000 |
5 | 114023223340300224440 |
6 | 1140420343513455320 |
7 | 36256165505503251 |
oct | 3545301756447300 |
9 | 561616735588173 |
10 | 130112003133120 |
11 | 38504210834958 |
12 | 127146b2711540 |
13 | 577a680a85558 |
14 | 241b651414b28 |
15 | 10097a2472080 |
hex | 76560fba4ec0 |
130112003133120 has 112 divisors (see below), whose sum is σ = 419877833250528. Its totient is φ = 34127738511360.
The previous prime is 130112003133053. The next prime is 130112003133131. The reversal of 130112003133120 is 21331300211031.
It is a happy number.
130112003133120 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1110870429 + ... + 1110987548.
Almost surely, 2130112003133120 is an apocalyptic number.
130112003133120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130112003133120 is an abundant number, since it is smaller than the sum of its proper divisors (289765830117408).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130112003133120 is a wasteful number, since it uses less digits than its factorization.
130112003133120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2221858058 (or 2221858048 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 130112003133120 its reverse (21331300211031), we get a palindrome (151443303344151).
The spelling of 130112003133120 in words is "one hundred thirty trillion, one hundred twelve billion, three million, one hundred thirty-three thousand, one hundred twenty".
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