Base | Representation |
---|---|
bin | 100101010101110100111… |
… | …0101101100110101000000 |
3 | 200011121212212010210110202 |
4 | 1022223221311230311000 |
5 | 1133041032203320000 |
6 | 14525354412344332 |
7 | 1036532400152510 |
oct | 112535165546500 |
9 | 20147785123422 |
10 | 5132114120000 |
11 | 16a95766992aa |
12 | 6aa77a7750a8 |
13 | 2b2c57c5b87a |
14 | 13a577935840 |
15 | 8d770e8add5 |
hex | 4aae9d6cd40 |
5132114120000 has 140 divisors (see below), whose sum is σ = 14543972314080. Its totient is φ = 1759581888000.
The previous prime is 5132114119991. The next prime is 5132114120017. The reversal of 5132114120000 is 214112315.
It is a tau number, because it is divible by the number of its divisors (140).
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 8884490 + ... + 9444489.
Almost surely, 25132114120000 is an apocalyptic number.
5132114120000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5132114120000 is an abundant number, since it is smaller than the sum of its proper divisors (9411858194080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5132114120000 is an equidigital number, since it uses as much as digits as its factorization.
5132114120000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18329018 (or 18328993 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 5132114120000 its reverse (214112315), we get a palindrome (5132328232315).
The spelling of 5132114120000 in words is "five trillion, one hundred thirty-two billion, one hundred fourteen million, one hundred twenty thousand".
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