Base | Representation |
---|---|
bin | 1011110101111110110011… |
… | …1100010010111000010000 |
3 | 1201002220010001002110210100 |
4 | 2331133230330102320100 |
5 | 3201323044400244440 |
6 | 43410122305132400 |
7 | 2512544552032251 |
oct | 275375474227020 |
9 | 51086101073710 |
10 | 13022021103120 |
11 | 417067647a477 |
12 | 156390862a100 |
13 | 735c81cb8953 |
14 | 3303aa8dab28 |
15 | 178aeca83230 |
hex | bd7ecf12e10 |
13022021103120 has 120 divisors (see below), whose sum is σ = 46304775083736. Its totient is φ = 3268271960064.
The previous prime is 13022021103073. The next prime is 13022021103131. The reversal of 13022021103120 is 2130112022031.
13022021103120 is a `hidden beast` number, since 1 + 302 + 20 + 21 + 10 + 312 + 0 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 5689255366656 + 7332765736464 = 2385216^2 + 2707908^2 .
It is a tau number, because it is divible by the number of its divisors (120).
It is a super-2 number, since 2×130220211031202 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 13022021103093 and 13022021103102.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 531933067 + ... + 531957546.
Almost surely, 213022021103120 is an apocalyptic number.
13022021103120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13022021103120 is an abundant number, since it is smaller than the sum of its proper divisors (33282753980616).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13022021103120 is a wasteful number, since it uses less digits than its factorization.
13022021103120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1063890649 (or 1063890640 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 13022021103120 its reverse (2130112022031), we get a palindrome (15152133125151).
The spelling of 13022021103120 in words is "thirteen trillion, twenty-two billion, twenty-one million, one hundred three thousand, one hundred twenty".
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