Base | Representation |
---|---|
bin | 100111001000111… |
… | …1000100111100000 |
3 | 10101112020010021120 |
4 | 1032101320213200 |
5 | 10142201424300 |
6 | 334152452240 |
7 | 44354650425 |
oct | 11621704740 |
9 | 3345203246 |
10 | 1313311200 |
11 | 61436a163 |
12 | 3079aa080 |
13 | 17c118a26 |
14 | c65c7d4c |
15 | 7a46e3a0 |
hex | 4e4789e0 |
1313311200 has 144 divisors (see below), whose sum is σ = 4526429040. Its totient is φ = 329605120.
The previous prime is 1313311159. The next prime is 1313311229. The reversal of 1313311200 is 21133131.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1313311200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 24706 + ... + 56894.
It is an arithmetic number, because the mean of its divisors is an integer number (31433535).
Almost surely, 21313311200 is an apocalyptic number.
1313311200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1313311200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2263214520).
1313311200 is an abundant number, since it is smaller than the sum of its proper divisors (3213117840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1313311200 is a wasteful number, since it uses less digits than its factorization.
1313311200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32229 (or 32216 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
The square root of 1313311200 is about 36239.6357597590. The cubic root of 1313311200 is about 1095.1053046076.
Adding to 1313311200 its reverse (21133131), we get a palindrome (1334444331).
The spelling of 1313311200 in words is "one billion, three hundred thirteen million, three hundred eleven thousand, two hundred".
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