Base | Representation |
---|---|
bin | 101010001101011010000 |
3 | 2121021021200 |
4 | 11101223100 |
5 | 323224440 |
6 | 45351200 |
7 | 14520264 |
oct | 5215320 |
9 | 2537250 |
10 | 1383120 |
11 | 865182 |
12 | 568500 |
13 | 39571b |
14 | 2800a4 |
15 | 1c4c30 |
hex | 151ad0 |
1383120 has 120 divisors (see below), whose sum is σ = 4961736. Its totient is φ = 344064.
The previous prime is 1383113. The next prime is 1383121. The reversal of 1383120 is 213831.
It can be written as a sum of positive squares in 4 ways, for example, as 28224 + 1354896 = 168^2 + 1164^2 .
It is a tau number, because it is divible by the number of its divisors (120).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 1383093 and 1383102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1383121) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12184 + ... + 12296.
21383120 is an apocalyptic number.
1383120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1383120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2480868).
1383120 is an abundant number, since it is smaller than the sum of its proper divisors (3578616).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1383120 is a wasteful number, since it uses less digits than its factorization.
1383120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 149 (or 140 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
The square root of 1383120 is about 1176.0612228962. The cubic root of 1383120 is about 111.4174686035.
Subtracting from 1383120 its product of nonzero digits (144), we obtain a square (1382976 = 11762).
Adding to 1383120 its reverse (213831), we get a palindrome (1596951).
The spelling of 1383120 in words is "one million, three hundred eighty-three thousand, one hundred twenty".
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