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211221310320 = 243251717256643
BaseRepresentation
bin1100010010110111000…
…1010110101101110000
3202012012101011022102100
43010231301112231300
511430040123412240
6241011141420400
721155155341306
oct3045561265560
9665171138370
10211221310320
118163aa17789
1234b2970a700
1316bc2052777
14a31a520276
15576367be30
hex312dc56b70

211221310320 has 120 divisors (see below), whose sum is σ = 751078173456. Its totient is φ = 53012404224.

The previous prime is 211221310277. The next prime is 211221310327. The reversal of 211221310320 is 23013122112.

211221310320 is a `hidden beast` number, since 2 + 1 + 12 + 21 + 310 + 320 = 666.

211221310320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (120).

It is a super-2 number, since 2×2112213103202 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 211221310293 and 211221310302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211221310327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8616082 + ... + 8640561.

Almost surely, 2211221310320 is an apocalyptic number.

211221310320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

211221310320 is an abundant number, since it is smaller than the sum of its proper divisors (539856863136).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211221310320 is a wasteful number, since it uses less digits than its factorization.

211221310320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17256679 (or 17256670 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 211221310320 its reverse (23013122112), we get a palindrome (234234432432).

The spelling of 211221310320 in words is "two hundred eleven billion, two hundred twenty-one million, three hundred ten thousand, three hundred twenty".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 16 17 18 20 24 30 34 36 40 45 48 51 60 68 72 80 85 90 102 120 136 144 153 170 180 204 240 255 272 306 340 360 408 510 612 680 720 765 816 1020 1224 1360 1530 2040 2448 3060 4080 6120 12240 17256643 34513286 51769929 69026572 86283215 103539858 138053144 155309787 172566430 207079716 258849645 276106288 293362931 310619574 345132860 414159432 517699290 586725862 621239148 690265720 776548935 828318864 880088793 1035398580 1173451724 1242478296 1380531440 1466814655 1553097870 1760177586 2070797160 2346903448 2484956592 2640266379 2933629310 3106195740 3520355172 4141594320 4400443965 4693806896 5280532758 5867258620 6212391480 7040710344 8800887930 10561065516 11734517240 12424782960 13201331895 14081420688 17601775860 21122131032 23469034480 26402663790 35203551720 42244262064 52805327580 70407103440 105610655160 211221310320